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IBDP Maths AA HL Predicted Paper 3 sample

Questions

Question 1

A pendant is formed by rotating a region about the xx-axis.

Consider the curve y=13x23x+1y=\dfrac{1}{\sqrt{3x^{2}-3x+1}} on the interval 12x1\dfrac12\le x\le1. The region RR (in cm\text{cm}) is bounded by this curve, the xx-axis, and the vertical lines x=12x=\dfrac12 and x=1x=1. When RR is rotated through 2π2\pi about the xx-axis, a solid (the pendant) is formed.

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Part a (i)
[2]

Show that 3x23x+1=3(x12)2+143x^{2}-3x+1=3\left(x-\dfrac12\right)^{2}+\dfrac14.

Part a (ii)
[3]

Hence find the exact coordinates of the maximum point of the curve on [12,1][\dfrac12,1] and state whether yy is increasing or decreasing on this interval.

Part b (i)
[2]

Write down an exact integral for the area AA of RR. State the units.

Part b (ii)
[2]

Use your GDC to evaluate AA to three significant figures.

Part c
[8]

When RR is rotated about the xx-axis, the volume VV is V=πx=12x=1y2,dxV=\pi\int_{x=\frac12}^{x=1} y^{2},dx.
Find an exact simplified value for VV and a numerical value to four significant figures.

Part d (i)
[5]

Consider y=1ax2+bx+cy=\dfrac{1}{\sqrt{ax^{2}+bx+c}}, where a>0a>0 and 4acb2>04ac-b^{2}>0.
(i) Show that dxax2+bx+c=24acb2tan1!(2ax+b4acb2)+C\int \dfrac{dx}{ax^{2}+bx+c}=\dfrac{2}{\sqrt{4ac-b^{2}}}\tan^{-1}!\left(\dfrac{2ax+b}{\sqrt{4ac-b^{2}}}\right)+C.

Part d (ii)
[3]

Hence obtain a general expression for the volume generated by rotating the region under yy from x=px=p to x=qx=q about the xx-axis.

Part d (iii)
[3]

Deduce a closed-form expression for the volume obtained by rotating the whole curve about the xx-axis from x=x=-\infty to x=+x=+\infty. State clearly the condition(s) required for this volume to be finite.

[28]

Question 2

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