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AP Calculus AB study notes

5.12.5 Second derivatives for implicit relations

AP Syllabus focus:
‘Second derivatives for implicit relations may involve x, y, and dy/dx, and are found by differentiating dy/dx implicitly again with respect to x.’

Second derivatives of implicit relations reveal how curves bend and change shape, extending concavity analysis to equations where y is not isolated as a function of x.

Understanding Second Derivatives in Implicit Contexts

When working with an implicit relation, we study an equation involving both x and y without rewriting it in explicit form. The second derivative gives insight into concavity and the curvature of the curve, even when expressing y directly as a function of x is difficult or impossible.

Implicit Relation: An equation involving x and y in which y is not already solved as a function of x.

Geometrically, an implicit relation defines a curve in the plane even when the graph fails the vertical line test or cannot be written as a single explicit function y=f(x)y=f(x)y=f(x).

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Folium of Descartes: an implicit curve defined by a single equation in xx and yy. The loop and extending branch illustrate that implicit relations can produce shapes that are not functions of xx. The specific equation extends slightly beyond the AP syllabus, but the image effectively visualizes curves analyzed using implicit first and second derivatives. Source.

Before second derivatives can be found, the first derivative must be obtained through implicit differentiation, which applies the derivative rules to both sides of the equation while treating y as a differentiable function of x. Only after this step can the second derivative be constructed.

Differentiating dy/dx Again with Respect to x

Once dydx \frac{dy}{dx} is known, the next step is to compute d2ydx2 \frac{d^2y}{dx^2} . Because most implicit derivatives include a mix of both x and y, the process requires careful attention to several ideas:

Key Principles When Differentiating dy/dx Again

  • Every appearance of y must be differentiated using the chain rule because y depends on x.

  • Expressions containing dydx \frac{dy}{dx} must be differentiated using product or quotient rules when appropriate.

  • The second derivative often involves all three quantities: x, y, and dydx \frac{dy}{dx} .

  • The final expression does not need to eliminate y unless a specific task requires it; the result is typically left implicit.

Because implicit relations frequently involve algebraic combinations of variables and derivatives, second derivatives tend to appear in more complex forms than their explicit-function counterparts.

Structure of a Second Derivative Expression

The second derivative is generally built by differentiating a rational or composite expression for dydx \frac{dy}{dx} . This requires applying differentiation rules systematically and substituting back wherever necessary.

d2ydx2=ddx(dydx) \frac{d^2y}{dx^2} = \frac{d}{dx}\left(\frac{dy}{dx}\right)
x,y x, y = Variables whose relationship is defined implicitly
dydx \frac{dy}{dx} = First derivative found using implicit differentiation
d2ydx2 \frac{d^2y}{dx^2} = Second derivative expressing concavity or curvature

A sentence following the equation helps clarify that differentiation rules from earlier topics apply fully here, but with the added complexity that both variables and derivatives must be handled simultaneously.

Processes for Finding Second Derivatives

The procedure for determining a second derivative for an implicit relation can be organized into a structured sequence that supports accuracy:

Step-by-Step Process

  • Differentiate the original equation implicitly to obtain dydx \frac{dy}{dx} .

  • Rewrite dydx \frac{dy}{dx} clearly, often as a single rational expression, to prepare for a second differentiation.

  • Differentiate dydx \frac{dy}{dx} with respect to x, applying:

    • the product rule when factors involve both x and y

    • the chain rule when differentiating any term containing y

    • the quotient rule if dydx \frac{dy}{dx} is expressed as a quotient

  • Replace each occurrence of dydx \frac{dy}{dx} that appears during the second differentiation with the original first derivative expression.

  • Simplify carefully, allowing the second derivative to remain in implicit form.

These steps ensure that no derivative of y is overlooked and no implicit dependence is ignored.

Interpreting Second Derivatives from Implicit Relations

Because implicit second derivatives incorporate x, y, and dydx \frac{dy}{dx} , interpreting them requires translating the expression into information about concavity or rate of change of slope.

Once d2y/dx2d^2y/dx^2d2y/dx2 has been computed for an implicit relation, its sign tells us whether the graph is bending upward (concave up) or bending downward (concave down) with respect to the x-axis.

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This graph illustrates a function that is concave up on some intervals and concave down on others. It demonstrates how a positive second derivative corresponds to upward curvature and a negative second derivative to downward curvature. The source discusses applications beyond the AP syllabus, but the visual depiction of concavity aligns directly with the study-note content. Source.

Using the Second Derivative to Describe Concavity

  • A positive second derivative indicates the curve is concave up, meaning its slope is increasing.

  • A negative second derivative indicates the curve is concave down, meaning its slope is decreasing.

  • If the second derivative changes sign across a point where it is defined, the curve experiences a change in concavity.

These interpretations follow the same principles used for explicit functions, even though the algebraic form is more involved.

Common Structures and Features of Implicit Second Derivatives

Second derivatives for implicit relations often arise in expressions with the following characteristics:

Frequent Characteristics

  • The presence of mixed variables, such as x terms multiplied by y terms.

  • Dependence on dy/dx, which appears as a component rather than a final standalone value.

  • Fractional forms created by quotient-rule applications.

  • Multi-layered expressions requiring substitution and simplification.

Because implicit curves may loop, turn, or fold over themselves, the second derivative provides valuable geometric insight that is not always visible from the original relation alone.

Importance of Mastery for Analysis

Understanding how to find and interpret second derivatives for implicit relations equips students to analyze curvature and concavity in a far broader class of curves than those defined explicitly. The process reinforces derivative concepts from earlier topics while extending them into richer mathematical settings involving interdependent variables.

FAQ

The second derivative of an implicit relation often contains a mixture of x, y, and dy/dx because y is not isolated as a function of x.

This means the differentiation rules interact in more complicated ways, requiring repeated product rule, chain rule and sometimes quotient rule applications.

The result typically cannot be simplified to a function of x alone, which is why implicit second derivatives usually remain in mixed-variable form.

Yes. Concavity depends on how the slope changes along the curve, not on whether the graph represents y as a single function of x.

Even if an implicit curve loops or turns vertically, the second derivative still measures whether the curve bends upward or downward as you move along it.

This allows concavity analysis in cases where explicit methods would not apply.

Whenever y appears in an expression, it must be treated as a differentiable function of x. This means each differentiation of a y-term produces an additional factor of dy/dx.

When differentiating dy/dx itself, any y-dependent components must also be differentiated with the chain rule.

This cascading dependency is what causes implicit second derivatives to contain dy/dx repeatedly.

It usually is, especially in AP-style questions. Substitution ensures consistency and avoids leaving mixed expressions where some dy/dx terms reflect original structure and others arise from new differentiation.

Substitution also allows the second derivative to be expressed in the simplest implicit form, making later evaluation at particular points more straightforward.

Simplification is helpful when:

• you will evaluate at a specific point,
• multiple dy/dx terms can be combined, or
• the structure is too complex to interpret clearly.

It is unnecessary when:

• the expression is already neatly factorised,
• simplification adds algebraic complexity, or
• the question only asks for a correct implicit form rather than a fully simplified expression.

Practice Questions

Question 1 (1–3 marks)
The curve is defined implicitly by the equation
x squared plus x y plus y squared equals 7.
(a) Find dy/dx.
(b) Hence find d²y/dx² in terms of x, y, and dy/dx.

Question 1

(a)
• Correct differentiation of each term (1 mark)
• Correct application of product rule to x y (1 mark)
• Correct simplified expression for dy/dx (1 mark)

(b)
• Differentiation of dy/dx using appropriate rules (product or quotient rule depending on the form used) (1 mark)
• Correct use of dy/dx when differentiating y terms (chain rule) (1 mark)
• Final expression for d²y/dx² in acceptable implicit form (1 mark)

Total: 3 marks

Question 2 (4–6 marks)
A curve is defined implicitly by
x cubed minus 2 x y plus y squared equals 5.

(a) Show that dy/dx equals (3 x squared minus 2 y) divided by (2 x minus 2 y).
(b) Find an expression for d²y/dx² in terms of x, y, and dy/dx.
(c) The point (1, 2) lies on the curve. Use your result for d²y/dx² to determine whether the curve is concave up or concave down at this point.

Question 2

(a)
• Correct implicit differentiation of each term (1 mark)
• Correct rearrangement to isolate dy/dx (1 mark)

(b)
• Differentiation of dy/dx with respect to x using correct rules (1 mark)
• Substitution of dy/dx where required (1 mark)
• Correct simplified expression for d²y/dx² (1 mark)

(c)
• Substitution of x, y, and dy/dx into the expression for d²y/dx² (1 mark)
• Correct determination of the sign of d²y/dx² (1 mark)
• Correct conclusion: concave up if positive, concave down if negative (1 mark)

Total: 6 marks

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